how to make echo get_i18n_link($slug) work ?

[Felix]

Hi,

To have a multilanguage menu in a site is by using:

<?php get_i18n_navigation(); ?>

However, I need to make a customized menu.

One way to make your own customized menu is by using:

 get_i18n_link($slug)
 
Example:

<ul>
<li><?php get_i18n_link(index); ?></li>
<li><?php get_i18n_link(about); ?></li>
<li><?php get_i18n_link(contact); ?></li>
</ul>

But in my case what I really need is this:

<?php
echo '<ul>';
echo '<li>' . get_i18n_link(about) . '</li>';
....
echo '</ul>';
?>

The problem here is that the part: echo get_i18n_link(about) does not work correctly
and outputs a 1

Is there a parameter to make echo get_i18n_link(about) work correctly

like echo get_i18n_link(about, false) or something like that ?

[Carlos]

Quotes are missing in your examples. It should be like this:

<?php get_i18n_link('about'); ?>

[Felix]

Thanks Carlos for your reply,

But no change,
somehow this still adds a 1 directly after the link
echo '<li>' . get_i18n_link('about') . '</li>';

On the front it looks like this
About1

I think with echo the 1 will always be added

Instead, will try to use <?php get_i18n_link('about'); ?>

[Bigin]

Do not use echo, the return value is already echoes.

Instead, just:

<ul>
<li><?php get_i18n_link('about') ?></li>
....

[Felix]

Guys,

Thanks for the replies. Yes in this case I have to change
my design using <?php ... instead of echo ...