QUESTION Load ajax subpage

[werty1001]

Hi. This code echo all subpage. How show only 10 subpage and another load after with ajax.

PHP Code:

function getSubMenu($page){ 

 $children=getChildren($page); 

 foreach ($children as $subpage){ 
    $title=returnPageField($subpage,'title'); 
    $url=returnPageField($subpage,'slug'); 
    echo '<a href="/'.$url.'.html"> '.$title.'</a>'; 
  }

} 


How make php function which show subpage (number from ajax). For example ajax:

Code:

$.ajax({  
                    type: "POST",  
                    url: "",
                    context: this,
                    data: {
                              'num'       : '10'
                           },
                    success: function(data){
                      console.log(data);
                    },
                    error: function(data){
                      console.log('error' + data);
                    }
                });

[shawn_a]

Slice the array using the page number via query string
See array_slice

[werty1001]

Slice the array using the page number via query string
See array_slice

Thanks, i add this code in functions.php

PHP Code:

if($_POST['ajaxload']) {

    $num = $_POST['ajaxload'];    
    $children=getChildren(news);
    $sliced = array_slice($children, 0, $num);
    
    foreach ($sliced as $subpage){
        $title=returnPageField($subpage,'title');
        $url=returnPageField($subpage,'slug');
        echo '<li><a href="/'.$url.'.html">'.$title.'</a></li>';
     }

} 


Code:

$('body').on('click', '#load', function() {

    
    $.ajax({  
                    type: "POST",  
                    url: "/theme/news/functions.php",
                    context: this,
                    data: {
                           ajaxload : '10'
                    },
                    success: function(data) {
             console.log(data);
                        alert(data);
                    },
                    error: function(output){
                      alert(resp);
                    }
                });
        
});

But onclick error

<b>Fatal error</b>: Call to undefined function getChildren()

[shawn_a]

are you tying to run this outside of GS ?
pretty sure thats is indeed a function in core, you are trying to load it directly outside of GS just submit to index not functions.

[werty1001]

are you tying to run this outside of GS ?
pretty sure thats is indeed a function in core, you are trying to load it directly outside of GS just submit to index not functions.

This php code is in functions.php my theme of GetSimple.

Simple code work

PHP Code:

if($_POST['ajaxload']) {

    $num = $_POST['ajaxload'];    
    $newnum = $num*2;
        echo ''.$newnum.'';
} 


return 20.

But when i try

PHP Code:

if($_POST['ajaxload']) {

    $num = $_POST['ajaxload'];    
    $children=getChildren(news);
    $sliced = array_slice($children, 0, $num);
    
    foreach ($sliced as $subpage){
        $title=returnPageField($subpage,'title');
        $url=returnPageField($subpage,'slug');
        echo '<li><a href="/'.$url.'.html">'.$title.'</a></li>';
    }

} 


return [object Object] and POST /functions.php 500 (Internal Server Error)

[shawn_a]

you do not send forms to your functions you send them to your index.
functions is loaded in global scope automatically and your code will run.

[shawn_a]

You also want to wrap it in a function and call in your template somehow if you want to use core functions

[werty1001]

you do not send forms to your functions you send them to your index.
functions is loaded in global scope automatically and your code will run.

You also want to wrap it in a function and call in your template somehow if you want to use core functions

I have bad english and knowledge of php , I still don't understand why it doesn't work.

Could you write a working example code?

[werty1001]

I make file ajax.php in my theme, global functions will be work when ajax call it? How i can do it work?