Custom Menu PHP Include

[lakaroth]

I'm sorry you right, but but i'm not expert, i really dont understand how to explain i try like this.

I have template.php file in theme folder, i have try to write in that file just before website content the code:

PHP Code:

<? include("filename.php"); ?>

or

PHP Code:

<?php include(GSTHEMESPATH.$TEMPLATE.'/filename.php'); ?>

I think is the same... anyway.

The result is this, my external menù appear wothout his css and others thing who let it work, is just a normal HTML text.

I dont know where to call CSS becaouse the CSS file are called in his own file (externalmenu.php) and if i try it alone it works.

If i try to call again in template.php file the css style like this:

PHP Code:

<link href="css/reset.css" rel="stylesheet" type="text/css" />
<link href="css/common.css" rel="stylesheet" type="text/css" />
<link href="css/facets3.css" rel="stylesheet" type="text/css" />
<link href='http://fonts.googleapis.com/css?family=Droid+Sans' rel='stylesheet' type='text/css'>
<link href="css/menu.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="js/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="js/common.js"></script>
<script type="text/javascript" src="js/jquery.clip.js"></script>
<script type="text/javascript" src="js/jquery.facets.js"></script>
<script type="text/javascript"> 


Then:

PHP Code:

<? include("filename.php"); ?>

Dont work...
Where i need to call CSS and others JS file to have a result like this?